Skip to main content

C Program to Multiply Two Floating-Point Numbers

 

Program to Multiply Two Numbers

#include <stdio.h>
int main() {
    double a, b, product;
    printf("Enter two numbers: ");
    scanf("%lf %lf", &a, &b);  
 
    // Calculating product
    product = a * b;

    // Result up to 2 decimal point is displayed using %.2lf
    printf("Product = %.2lf", product);
    
    return 0;
}

Output

Enter two numbers: 2.4
1.12
Product = 2.69

In this program, the user is asked to enter two numbers which are stored in variables a and b respectively.

printf("Enter two numbers: ");
scanf("%lf %lf", &a, &b); 

Then, the product of a and b is evaluated and the result is stored in product.

product = a * b;

Finally, product is displayed on the screen using printf().

printf("Product = %.2lf", product);

Notice that, the result is rounded off to the second decimal place using %.2lf conversion character.

Comments

Popular posts from this blog

C Program to Calculate Difference Between Two Time Periods

  Calculate Difference Between Two Time Periods # include <stdio.h> struct TIME { int seconds; int minutes; int hours; }; void differenceBetweenTimePeriod (struct TIME t1, struct TIME t2, struct TIME *diff) ; int main () { struct TIME startTime , stopTime , diff ; printf ( "Enter the start time. \n" ); printf ( "Enter hours, minutes and seconds: " ); scanf ( "%d %d %d" , &startTime.hours, &startTime.minutes, &startTime.seconds); printf ( "Enter the stop time. \n" ); printf ( "Enter hours, minutes and seconds: " ); scanf ( "%d %d %d" , &stopTime.hours, &stopTime.minutes, &stopTime.seconds); // Difference between start and stop time differenceBetweenTimePeriod(startTime, stopTime, &diff); printf ( "\nTime Difference: %d:%d:%d - ...

C program to calculate the power using recursion

  Program to calculate power using recursion # include <stdio.h> int power ( int n1, int n2) ; int main () { int base, a, result; printf ( "Enter base number: " ); scanf ( "%d" , &base); printf ( "Enter power number(positive integer): " ); scanf ( "%d" , &a); result = power(base, a); printf ( "%d^%d = %d" , base, a, result); return 0 ; } int power ( int base, int a) { if (a != 0 ) return (base * power(base, a - 1 )); else return 1 ; } Output Enter base number: 3 Enter power number(positive integer): 4 3^4 = 81

Simple Calculator in c language

#include   <stdio.h> #include   <string.h> #include   <math.h> #include   <stdlib.h> int   main () {         int  a, b;      scanf ( "%d" , &a);      scanf ( "%d" , &b);      printf ( "%d \n " , a + b);      printf ( "%d \n " , a - b);      printf ( "%d \n " , a * b);      printf ( "%d \n " , a / b);      return   0 ; }